3x^2+63x-105=0

Solution for 3x^2+63x-105=0 equation:

3x^2+63x-105=0

a = 3; b = 63; c = -105;
Δ = b2-4ac
Δ = 632-4·3·(-105)
Δ = 5229
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5229}=\sqrt{9*581}=\sqrt{9}*\sqrt{581}=3\sqrt{581}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(63)-3\sqrt{581}}{2*3}=\frac{-63-3\sqrt{581}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(63)+3\sqrt{581}}{2*3}=\frac{-63+3\sqrt{581}}{6}
$